Search a number
-
+
20031441 = 36677147
BaseRepresentation
bin100110001101…
…0011111010001
31101200200222020
41030122133101
520112001231
61553202053
7332156463
oct114323721
941620866
1020031441
1110341a11
126860329
1341c4831
142936133
151b5a396
hex131a7d1

20031441 has 4 divisors (see below), whose sum is σ = 26708592. Its totient is φ = 13354292.

The previous prime is 20031439. The next prime is 20031449. The reversal of 20031441 is 14413002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20031441 - 21 = 20031439 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20031441.

It is not an unprimeable number, because it can be changed into a prime (20031449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3338571 + ... + 3338576.

It is an arithmetic number, because the mean of its divisors is an integer number (6677148).

Almost surely, 220031441 is an apocalyptic number.

It is an amenable number.

20031441 is a deficient number, since it is larger than the sum of its proper divisors (6677151).

20031441 is an equidigital number, since it uses as much as digits as its factorization.

20031441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6677150.

The product of its (nonzero) digits is 96, while the sum is 15.

The square root of 20031441 is about 4475.6497852267. The cubic root of 20031441 is about 271.5839271955.

Adding to 20031441 its reverse (14413002), we get a palindrome (34444443).

The spelling of 20031441 in words is "twenty million, thirty-one thousand, four hundred forty-one".

Divisors: 1 3 6677147 20031441