Base | Representation |
---|---|
bin | 11101001001101000000… |
… | …010010111010001010011 |
3 | 21002111121110121100210111 |
4 | 131021220002113101103 |
5 | 230310023223210003 |
6 | 4132131340342151 |
7 | 264504111561256 |
oct | 35115002272123 |
9 | 7074543540714 |
10 | 2003200210003 |
11 | 702609327a43 |
12 | 284297844957 |
13 | 116b93577665 |
14 | 6cd538d109d |
15 | 37193e1ce6d |
hex | 1d268097453 |
2003200210003 has 4 divisors (see below), whose sum is σ = 2067819571648. Its totient is φ = 1938580848360.
The previous prime is 2003200209953. The next prime is 2003200210013. The reversal of 2003200210003 is 3000120023002.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2003200210003 is a prime.
It is a super-2 number, since 2×20032002100032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2003200210013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32309680776 + ... + 32309680837.
It is an arithmetic number, because the mean of its divisors is an integer number (516954892912).
Almost surely, 22003200210003 is an apocalyptic number.
2003200210003 is a deficient number, since it is larger than the sum of its proper divisors (64619361645).
2003200210003 is an equidigital number, since it uses as much as digits as its factorization.
2003200210003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64619361644.
The product of its (nonzero) digits is 72, while the sum is 13.
Adding to 2003200210003 its reverse (3000120023002), we get a palindrome (5003320233005).
The spelling of 2003200210003 in words is "two trillion, three billion, two hundred million, two hundred ten thousand, three".
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