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2003201211103 = 17156837513573
BaseRepresentation
bin11101001001101000000…
…110001011101011011111
321002111121112111020001021
4131021220012023223133
5230310024002223403
64132131414025011
7264504123231031
oct35115006135337
97074545436037
102003201211103
117026099510a4
12284298048167
13116b93838221
146cd53ab1c51
15371940698bd
hex1d26818badf

2003201211103 has 8 divisors (see below), whose sum is σ = 2121172103088. Its totient is φ = 1885245377664.

The previous prime is 2003201211097. The next prime is 2003201211107. The reversal of 2003201211103 is 3011121023002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2003201211103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003201211107) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3490176 + ... + 4023397.

It is an arithmetic number, because the mean of its divisors is an integer number (265146512886).

Almost surely, 22003201211103 is an apocalyptic number.

2003201211103 is a deficient number, since it is larger than the sum of its proper divisors (117970891985).

2003201211103 is a wasteful number, since it uses less digits than its factorization.

2003201211103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7529273.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 2003201211103 its reverse (3011121023002), we get a palindrome (5014322234105).

The spelling of 2003201211103 in words is "two trillion, three billion, two hundred one million, two hundred eleven thousand, one hundred three".

Divisors: 1 17 15683 266611 7513573 127730741 117835365359 2003201211103