200321120213 has 4 divisors (see below), whose sum is σ = 200322021900. Its totient is φ = 200320218528.

The previous prime is 200321120179. The next prime is 200321120243. The reversal of 200321120213 is 312021123002.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 139283464849 + 61037655364 = 373207^2 + 247058^2 .

It is a cyclic number.

It is not a de Polignac number, because 200321120213 - 2¹⁸ = 200320858069 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200321120191 and 200321120200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200321120243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 144113 + ... + 649161.

It is an arithmetic number, because the mean of its divisors is an integer number (50080505475).

Almost surely, 2^200321120213 is an apocalyptic number.

It is an amenable number.

200321120213 is a deficient number, since it is larger than the sum of its proper divisors (901687).

200321120213 is an equidigital number, since it uses as much as digits as its factorization.

200321120213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 901686.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 200321120213 its reverse (312021123002), we get a palindrome (512342243215).

The spelling of 200321120213 in words is "two hundred billion, three hundred twenty-one million, one hundred twenty thousand, two hundred thirteen".