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2003220012103 = 3761532629623
BaseRepresentation
bin11101001001101001001…
…101111001110001000111
321002111122211212102011121
4131021221031321301013
5230310043310341403
64132133325014411
7264504442104322
oct35115115716107
97074584772147
102003220012103
11702619522612
122842a23b4407
13116b976bb98b
146cd563a77b9
1537195a303bd
hex1d269379c47

2003220012103 has 4 divisors (see below), whose sum is σ = 2003752645488. Its totient is φ = 2002687378720.

The previous prime is 2003220012071. The next prime is 2003220012107. The reversal of 2003220012103 is 3012100223002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2003220012103 - 25 = 2003220012071 is a prime.

It is a super-3 number, since 3×20032200121033 (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003220012107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 266311051 + ... + 266318572.

It is an arithmetic number, because the mean of its divisors is an integer number (500938161372).

Almost surely, 22003220012103 is an apocalyptic number.

2003220012103 is a deficient number, since it is larger than the sum of its proper divisors (532633385).

2003220012103 is an equidigital number, since it uses as much as digits as its factorization.

2003220012103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 532633384.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 2003220012103 its reverse (3012100223002), we get a palindrome (5015320235105).

The spelling of 2003220012103 in words is "two trillion, three billion, two hundred twenty million, twelve thousand, one hundred three".

Divisors: 1 3761 532629623 2003220012103