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2003315225413 = 2579776779847
BaseRepresentation
bin11101001001101110111…
…001000111001101000101
321002111220111000202021111
4131021232321013031011
5230310242144203123
64132151005445021
7264510006312205
oct35115671071505
97074814022244
102003315225413
117026682447a7
1228430a270771
13116bb1347808
146cd64cb0405
153719e08b90d
hex1d26ee47345

2003315225413 has 4 divisors (see below), whose sum is σ = 2004092007840. Its totient is φ = 2002538442988.

The previous prime is 2003315225399. The next prime is 2003315225441. The reversal of 2003315225413 is 3145225133002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2003315225413 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003315225213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 388387345 + ... + 388392502.

It is an arithmetic number, because the mean of its divisors is an integer number (501023001960).

Almost surely, 22003315225413 is an apocalyptic number.

It is an amenable number.

2003315225413 is a deficient number, since it is larger than the sum of its proper divisors (776782427).

2003315225413 is an equidigital number, since it uses as much as digits as its factorization.

2003315225413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 776782426.

The product of its (nonzero) digits is 21600, while the sum is 31.

The spelling of 2003315225413 in words is "two trillion, three billion, three hundred fifteen million, two hundred twenty-five thousand, four hundred thirteen".

Divisors: 1 2579 776779847 2003315225413