20033411201101 has 4 divisors (see below), whose sum is σ = 20037763456672. Its totient is φ = 20029058945532.

The previous prime is 20033411201099. The next prime is 20033411201137. The reversal of 20033411201101 is 10110211433002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20033411201101 - 2¹ = 20033411201099 is a prime.

It is a super-2 number, since 2×20033411201101² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20033411201701) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2176120881 + ... + 2176130086.

It is an arithmetic number, because the mean of its divisors is an integer number (5009440864168).

Almost surely, 2^{20033411201101} is an apocalyptic number.

It is an amenable number.

20033411201101 is a deficient number, since it is larger than the sum of its proper divisors (4352255571).

20033411201101 is an equidigital number, since it uses as much as digits as its factorization.

20033411201101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4352255570.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 20033411201101 its reverse (10110211433002), we get a palindrome (30143622634103).

The spelling of 20033411201101 in words is "twenty trillion, thirty-three billion, four hundred eleven million, two hundred one thousand, one hundred one".