Base | Representation |
---|---|
bin | 101101100011010000110000… |
… | …010100001101101101110111 |
3 | 222021022212100002011211110121 |
4 | 231203100300110031231313 |
5 | 202224243110340110210 |
6 | 1550024430021232411 |
7 | 60124513425205654 |
oct | 5543206024155567 |
9 | 867285302154417 |
10 | 200335265160055 |
11 | 589187884a9323 |
12 | 1a576396b62707 |
13 | 87a26c42312ac |
14 | 37683c8576c2b |
15 | 18262a77096da |
hex | b6343050db77 |
200335265160055 has 16 divisors (see below), whose sum is σ = 250025743069344. Its totient is φ = 153974797764480.
The previous prime is 200335265159983. The next prime is 200335265160091. The reversal of 200335265160055 is 550061562533002.
200335265160055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 200335265160055 - 225 = 200335231605623 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 200335265159993 and 200335265160020.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7637625664 + ... + 7637651893.
It is an arithmetic number, because the mean of its divisors is an integer number (15626608941834).
Almost surely, 2200335265160055 is an apocalyptic number.
200335265160055 is a deficient number, since it is larger than the sum of its proper divisors (49690477909289).
200335265160055 is a wasteful number, since it uses less digits than its factorization.
200335265160055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15275277666.
The product of its (nonzero) digits is 810000, while the sum is 43.
The spelling of 200335265160055 in words is "two hundred trillion, three hundred thirty-five billion, two hundred sixty-five million, one hundred sixty thousand, fifty-five".
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