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200340151 = 1118212741
BaseRepresentation
bin10111111000011…
…11001010110111
3111221222100000121
423330033022313
5402241341101
631513552411
74651602034
oct1374171267
9457870017
10200340151
11a30a5580
1257115707
133267608b
141c87038b
15128c50a1
hexbf0f2b7

200340151 has 4 divisors (see below), whose sum is σ = 218552904. Its totient is φ = 182127400.

The previous prime is 200340137. The next prime is 200340181. The reversal of 200340151 is 151043002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200340151 is a prime.

It is a super-2 number, since 2×2003401512 = 80272352205405602, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200340181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9106360 + ... + 9106381.

It is an arithmetic number, because the mean of its divisors is an integer number (54638226).

Almost surely, 2200340151 is an apocalyptic number.

200340151 is a deficient number, since it is larger than the sum of its proper divisors (18212753).

200340151 is a wasteful number, since it uses less digits than its factorization.

200340151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18212752.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 200340151 is about 14154.1566686257. The cubic root of 200340151 is about 585.1348957188.

Adding to 200340151 its reverse (151043002), we get a palindrome (351383153).

The spelling of 200340151 in words is "two hundred million, three hundred forty thousand, one hundred fifty-one".

Divisors: 1 11 18212741 200340151