200340414113 has 4 divisors (see below), whose sum is σ = 228960473280. Its totient is φ = 171720354948.

The previous prime is 200340414073. The next prime is 200340414151. The reversal of 200340414113 is 311414043002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311414043002 = 2 ⋅155707021501.

It is a cyclic number.

It is not a de Polignac number, because 200340414113 - 2¹⁶ = 200340348577 is a prime.

It is not an unprimeable number, because it can be changed into a prime (200340414613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14310029573 + ... + 14310029586.

It is an arithmetic number, because the mean of its divisors is an integer number (57240118320).

Almost surely, 2^200340414113 is an apocalyptic number.

It is an amenable number.

200340414113 is a deficient number, since it is larger than the sum of its proper divisors (28620059167).

200340414113 is an equidigital number, since it uses as much as digits as its factorization.

200340414113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28620059166.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 200340414113 its reverse (311414043002), we get a palindrome (511754457115).

The spelling of 200340414113 in words is "two hundred billion, three hundred forty million, four hundred fourteen thousand, one hundred thirteen".