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20034344041 = 43945636319
BaseRepresentation
bin10010101010001000…
…111101010001101001
31220201020011010102021
4102222020331101221
5312012243002131
613111553304441
71306320054205
oct225210752151
956636133367
1020034344041
118550957228
123a71565121
131b73840c5a
14d80aa5b05
157c3ca1e11
hex4aa23d469

20034344041 has 4 divisors (see below), whose sum is σ = 20079980800. Its totient is φ = 19988707284.

The previous prime is 20034343999. The next prime is 20034344101. The reversal of 20034344041 is 14044343002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20034344041 - 215 = 20034311273 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20034343997 and 20034344015.

It is not an unprimeable number, because it can be changed into a prime (20034348041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22817721 + ... + 22818598.

It is an arithmetic number, because the mean of its divisors is an integer number (5019995200).

Almost surely, 220034344041 is an apocalyptic number.

It is an amenable number.

20034344041 is a deficient number, since it is larger than the sum of its proper divisors (45636759).

20034344041 is an equidigital number, since it uses as much as digits as its factorization.

20034344041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45636758.

The product of its (nonzero) digits is 4608, while the sum is 25.

Adding to 20034344041 its reverse (14044343002), we get a palindrome (34078687043).

The spelling of 20034344041 in words is "twenty billion, thirty-four million, three hundred forty-four thousand, forty-one".

Divisors: 1 439 45636319 20034344041