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2003440010042 = 21001720005021
BaseRepresentation
bin11101001001110110010…
…101001000001100111010
321002112020011211110121102
4131021312111020030322
5230311021120310132
64132211224211402
7264513053051612
oct35116625101472
97075204743542
102003440010042
11702721724299
12284344009b62
13116c01158483
146cd776b3a42
15371a9ed9c62
hex1d27654833a

2003440010042 has 4 divisors (see below), whose sum is σ = 3005160015066. Its totient is φ = 1001720005020.

The previous prime is 2003440010041. The next prime is 2003440010051. The reversal of 2003440010042 is 2400100443002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1402971549841 + 600468460201 = 1184471^2 + 774899^2 .

It is a junction number, because it is equal to n+sod(n) for n = 2003440009996 and 2003440010023.

It is not an unprimeable number, because it can be changed into a prime (2003440010041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500860002509 + ... + 500860002512.

Almost surely, 22003440010042 is an apocalyptic number.

2003440010042 is a deficient number, since it is larger than the sum of its proper divisors (1001720005024).

2003440010042 is a wasteful number, since it uses less digits than its factorization.

2003440010042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1001720005023.

The product of its (nonzero) digits is 768, while the sum is 20.

Adding to 2003440010042 its reverse (2400100443002), we get a palindrome (4403540453044).

The spelling of 2003440010042 in words is "two trillion, three billion, four hundred forty million, ten thousand, forty-two".

Divisors: 1 2 1001720005021 2003440010042