200344113356053 has 4 divisors (see below), whose sum is σ = 200344141942048. Its totient is φ = 200344084770060.

The previous prime is 200344113356029. The next prime is 200344113356087. The reversal of 200344113356053 is 350653311443002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 200344113356053 - 2²⁹ = 200343576485141 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200344113355997 and 200344113356015.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200344113353053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4166950 + ... + 20446312.

It is an arithmetic number, because the mean of its divisors is an integer number (50086035485512).

Almost surely, 2^{200344113356053} is an apocalyptic number.

It is an amenable number.

200344113356053 is a deficient number, since it is larger than the sum of its proper divisors (28585995).

200344113356053 is a wasteful number, since it uses less digits than its factorization.

200344113356053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28585994.

The product of its (nonzero) digits is 388800, while the sum is 40.

Adding to 200344113356053 its reverse (350653311443002), we get a palindrome (550997424799055).

The spelling of 200344113356053 in words is "two hundred trillion, three hundred forty-four billion, one hundred thirteen million, three hundred fifty-six thousand, fifty-three".