Base | Representation |
---|---|
bin | 101101100011011001000110… |
… | …110010011000110011001011 |
3 | 222021100201111000001201212211 |
4 | 231203121012302120303023 |
5 | 202224414441404244430 |
6 | 1550032511502045551 |
7 | 60125251560030052 |
oct | 5543310662306313 |
9 | 867321430051784 |
10 | 200344232103115 |
11 | 5892156a071371 |
12 | 1a578079b798b7 |
13 | 87a34c2ba9069 |
14 | 37689d9425399 |
15 | 182662ea5672a |
hex | b63646c98ccb |
200344232103115 has 48 divisors (see below), whose sum is σ = 268917476198400. Its totient is φ = 142860688492032.
The previous prime is 200344232102813. The next prime is 200344232103121. The reversal of 200344232103115 is 511301232443002.
200344232103115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 200344232103115 - 223 = 200344223714507 is a prime.
It is a super-2 number, since 2×2003442321031152 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 81678102 + ... + 84095188.
It is an arithmetic number, because the mean of its divisors is an integer number (5602447420800).
Almost surely, 2200344232103115 is an apocalyptic number.
200344232103115 is a deficient number, since it is larger than the sum of its proper divisors (68573244095285).
200344232103115 is a wasteful number, since it uses less digits than its factorization.
200344232103115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2420164 (or 2420147 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 200344232103115 its reverse (511301232443002), we get a palindrome (711645464546117).
The spelling of 200344232103115 in words is "two hundred trillion, three hundred forty-four billion, two hundred thirty-two million, one hundred three thousand, one hundred fifteen".
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