Base | Representation |
---|---|
bin | 101101100011100001010111… |
… | …011000110010110110100111 |
3 | 222021101120101001121002002020 |
4 | 231203201113120302312213 |
5 | 202230041122214310401 |
6 | 1550040535503314223 |
7 | 60126014414354112 |
oct | 5543412730626647 |
9 | 867346331532066 |
10 | 200353100541351 |
11 | 5892530007426a |
12 | 1a579933bab973 |
13 | 87a42a7314a54 |
14 | 37691db191579 |
15 | 182699d3e6d36 |
hex | b63857632da7 |
200353100541351 has 8 divisors (see below), whose sum is σ = 267137960795904. Its totient is φ = 133568486990520.
The previous prime is 200353100541311. The next prime is 200353100541379. The reversal of 200353100541351 is 153145001353002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 200353100541351 - 29 = 200353100540839 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200353100541311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59772591 + ... + 63035456.
It is an arithmetic number, because the mean of its divisors is an integer number (33392245099488).
Almost surely, 2200353100541351 is an apocalyptic number.
200353100541351 is a deficient number, since it is larger than the sum of its proper divisors (66784860254553).
200353100541351 is a wasteful number, since it uses less digits than its factorization.
200353100541351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 123351861.
The product of its (nonzero) digits is 27000, while the sum is 33.
Adding to 200353100541351 its reverse (153145001353002), we get a palindrome (353498101894353).
The spelling of 200353100541351 in words is "two hundred trillion, three hundred fifty-three billion, one hundred million, five hundred forty-one thousand, three hundred fifty-one".
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