Base | Representation |
---|---|
bin | 101101100011100001110000… |
… | …000010100001101011101111 |
3 | 222021101121102212211202212221 |
4 | 231203201300002201223233 |
5 | 202230042444104244010 |
6 | 1550041044520140211 |
7 | 60126030566011246 |
oct | 5543416002415357 |
9 | 867347385752787 |
10 | 200353514134255 |
11 | 589254a2583789 |
12 | 1a579a2a607667 |
13 | 87a4341c05391 |
14 | 376923a09395d |
15 | 18269c4892dda |
hex | b638700a1aef |
200353514134255 has 4 divisors (see below), whose sum is σ = 240424216961112. Its totient is φ = 160282811307400.
The previous prime is 200353514134247. The next prime is 200353514134261. The reversal of 200353514134255 is 552431415353002.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 200353514134255 - 23 = 200353514134247 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20035351413421 + ... + 20035351413430.
It is an arithmetic number, because the mean of its divisors is an integer number (60106054240278).
Almost surely, 2200353514134255 is an apocalyptic number.
200353514134255 is a deficient number, since it is larger than the sum of its proper divisors (40070702826857).
200353514134255 is an equidigital number, since it uses as much as digits as its factorization.
200353514134255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40070702826856.
The product of its (nonzero) digits is 1080000, while the sum is 43.
Adding to 200353514134255 its reverse (552431415353002), we get a palindrome (752784929487257).
The spelling of 200353514134255 in words is "two hundred trillion, three hundred fifty-three billion, five hundred fourteen million, one hundred thirty-four thousand, two hundred fifty-five".
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