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200353514134551 = 3896315973466483
BaseRepresentation
bin101101100011100001110000…
…000010100001110000010111
3222021101121102212211210021220
4231203201300002201300113
5202230042444104301201
61550041044520141423
760126030566012151
oct5543416002416027
9867347385753256
10200353514134551
11589254a2583a28
121a579a2a607873
1387a4341c0555b
14376923a093ad1
1518269c4893036
hexb638700a1c17

200353514134551 has 16 divisors (see below), whose sum is σ = 267185122356096. Its totient is φ = 133545459633696.

The previous prime is 200353514134493. The next prime is 200353514134591. The reversal of 200353514134551 is 155431415353002.

It is not a de Polignac number, because 200353514134551 - 210 = 200353514133527 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200353514134591) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 429264756 + ... + 429731238.

It is an arithmetic number, because the mean of its divisors is an integer number (16699070147256).

Almost surely, 2200353514134551 is an apocalyptic number.

200353514134551 is a deficient number, since it is larger than the sum of its proper divisors (66831608221545).

200353514134551 is a wasteful number, since it uses less digits than its factorization.

200353514134551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 491422.

The product of its (nonzero) digits is 540000, while the sum is 42.

Adding to 200353514134551 its reverse (155431415353002), we get a palindrome (355784929487553).

The spelling of 200353514134551 in words is "two hundred trillion, three hundred fifty-three billion, five hundred fourteen million, one hundred thirty-four thousand, five hundred fifty-one".

Divisors: 1 3 8963 15973 26889 47919 466483 1399449 143165999 429497997 4181087129 7451132959 12543261387 22353398877 66784504711517 200353514134551