Base | Representation |
---|---|
bin | 101101100011100001110000… |
… | …000010100001110000010111 |
3 | 222021101121102212211210021220 |
4 | 231203201300002201300113 |
5 | 202230042444104301201 |
6 | 1550041044520141423 |
7 | 60126030566012151 |
oct | 5543416002416027 |
9 | 867347385753256 |
10 | 200353514134551 |
11 | 589254a2583a28 |
12 | 1a579a2a607873 |
13 | 87a4341c0555b |
14 | 376923a093ad1 |
15 | 18269c4893036 |
hex | b638700a1c17 |
200353514134551 has 16 divisors (see below), whose sum is σ = 267185122356096. Its totient is φ = 133545459633696.
The previous prime is 200353514134493. The next prime is 200353514134591. The reversal of 200353514134551 is 155431415353002.
It is not a de Polignac number, because 200353514134551 - 210 = 200353514133527 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200353514134591) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 429264756 + ... + 429731238.
It is an arithmetic number, because the mean of its divisors is an integer number (16699070147256).
Almost surely, 2200353514134551 is an apocalyptic number.
200353514134551 is a deficient number, since it is larger than the sum of its proper divisors (66831608221545).
200353514134551 is a wasteful number, since it uses less digits than its factorization.
200353514134551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 491422.
The product of its (nonzero) digits is 540000, while the sum is 42.
Adding to 200353514134551 its reverse (155431415353002), we get a palindrome (355784929487553).
The spelling of 200353514134551 in words is "two hundred trillion, three hundred fifty-three billion, five hundred fourteen million, one hundred thirty-four thousand, five hundred fifty-one".
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