Base | Representation |
---|---|
bin | 1011101010011000011… |
… | …0000110110110101111 |
3 | 201011011002111100220011 |
4 | 2322212012012312233 |
5 | 11240311402130130 |
6 | 232013013234051 |
7 | 20321662242001 |
oct | 2724606066657 |
9 | 634132440804 |
10 | 200355114415 |
11 | 77a74269995 |
12 | 329b6632927 |
13 | 15b7ca76251 |
14 | 99a9320371 |
15 | 532971d52a |
hex | 2ea6186daf |
200355114415 has 4 divisors (see below), whose sum is σ = 240426137304. Its totient is φ = 160284091528.
The previous prime is 200355114409. The next prime is 200355114433. The reversal of 200355114415 is 514411553002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200355114415 - 25 = 200355114383 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20035511437 + ... + 20035511446.
It is an arithmetic number, because the mean of its divisors is an integer number (60106534326).
Almost surely, 2200355114415 is an apocalyptic number.
200355114415 is a deficient number, since it is larger than the sum of its proper divisors (40071022889).
200355114415 is an equidigital number, since it uses as much as digits as its factorization.
200355114415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40071022888.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 200355114415 its reverse (514411553002), we get a palindrome (714766667417).
The spelling of 200355114415 in words is "two hundred billion, three hundred fifty-five million, one hundred fourteen thousand, four hundred fifteen".
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