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2004032132015 = 53738332826143
BaseRepresentation
bin11101001010011001100…
…111111001001110101111
321002120202110000101020212
4131022121213321032233
5230313224211211030
64132350055333035
7264533533030004
oct35123147711657
97076673011225
102004032132015
117029a59912a1
1228448a38117b
13116c96a262c4
146cdd21a98ab
15371e1e9d595
hex1d2999f93af

2004032132015 has 16 divisors (see below), whose sum is σ = 2470479429888. Its totient is φ = 1559487764736.

The previous prime is 2004032131991. The next prime is 2004032132083. The reversal of 2004032132015 is 5102312304002.

It is a cyclic number.

It is not a de Polignac number, because 2004032132015 - 26 = 2004032131951 is a prime.

It is a super-2 number, since 2×20040321320152 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 703967 + ... + 2122176.

It is an arithmetic number, because the mean of its divisors is an integer number (154404964368).

Almost surely, 22004032132015 is an apocalyptic number.

2004032132015 is a deficient number, since it is larger than the sum of its proper divisors (466447297873).

2004032132015 is a wasteful number, since it uses less digits than its factorization.

2004032132015 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2830018.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 2004032132015 its reverse (5102312304002), we get a palindrome (7106344436017).

The spelling of 2004032132015 in words is "two trillion, four billion, thirty-two million, one hundred thirty-two thousand, fifteen".

Divisors: 1 5 37 185 3833 19165 141821 709105 2826143 14130715 104567291 522836455 10832606119 54163030595 400806426403 2004032132015