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2004113143 = 85911512027
BaseRepresentation
bin111011101110100…
…0101011011110111
312011200002111101201
41313131011123313
513101023110033
6530511033331
7100443452314
oct16735053367
95150074351
102004113143
119392a695a
1247b20b847
1325c287586
14150249d0b
15bae2647d
hex777456f7

2004113143 has 8 divisors (see below), whose sum is σ = 2009180160. Its totient is φ = 1999054200.

The previous prime is 2004113129. The next prime is 2004113161. The reversal of 2004113143 is 3413114002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2004113143 - 213 = 2004104951 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2004113143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2004113113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 987696 + ... + 989722.

It is an arithmetic number, because the mean of its divisors is an integer number (251147520).

Almost surely, 22004113143 is an apocalyptic number.

2004113143 is a deficient number, since it is larger than the sum of its proper divisors (5067017).

2004113143 is a wasteful number, since it uses less digits than its factorization.

2004113143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4037.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 2004113143 is about 44767.3222674754. The cubic root of 2004113143 is about 1260.7841643873.

Adding to 2004113143 its reverse (3413114002), we get a palindrome (5417227145).

The spelling of 2004113143 in words is "two billion, four million, one hundred thirteen thousand, one hundred forty-three".

Divisors: 1 859 1151 2027 988709 1741193 2333077 2004113143