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200412251241 = 366804083747
BaseRepresentation
bin1011101010100110000…
…0000100010001101001
3201011022002000012212220
42322221200010101221
511240421014014431
6232022414024253
720323255012446
oct2725140042151
9634262005786
10200412251241
1177aa3544704
1232a117a8089
1315b8b85cc17
1499b2b549cd
15532e757b96
hex2ea9804469

200412251241 has 4 divisors (see below), whose sum is σ = 267216334992. Its totient is φ = 133608167492.

The previous prime is 200412251233. The next prime is 200412251297. The reversal of 200412251241 is 142152214002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200412251241 - 23 = 200412251233 is a prime.

It is not an unprimeable number, because it can be changed into a prime (200412251231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33402041871 + ... + 33402041876.

It is an arithmetic number, because the mean of its divisors is an integer number (66804083748).

Almost surely, 2200412251241 is an apocalyptic number.

It is an amenable number.

200412251241 is a deficient number, since it is larger than the sum of its proper divisors (66804083751).

200412251241 is an equidigital number, since it uses as much as digits as its factorization.

200412251241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66804083750.

The product of its (nonzero) digits is 1280, while the sum is 24.

Adding to 200412251241 its reverse (142152214002), we get a palindrome (342564465243).

The spelling of 200412251241 in words is "two hundred billion, four hundred twelve million, two hundred fifty-one thousand, two hundred forty-one".

Divisors: 1 3 66804083747 200412251241