Base | Representation |
---|---|
bin | 101101100100011001001111… |
… | …110111111010101000110010 |
3 | 222021121022020210201211021200 |
4 | 231210121033313322220302 |
5 | 202232032014112232424 |
6 | 1550124301534232030 |
7 | 60133240355505462 |
oct | 5544311767725062 |
9 | 867538223654250 |
10 | 200413104024114 |
11 | 589487a150aa43 |
12 | 1a58949b055616 |
13 | 87a9b4a6c1237 |
14 | 376c0902adba2 |
15 | 18283110d68c9 |
hex | b6464fdfaa32 |
200413104024114 has 48 divisors (see below), whose sum is σ = 435295863475200. Its totient is φ = 66640227591168.
The previous prime is 200413104024103. The next prime is 200413104024131. The reversal of 200413104024114 is 411420401314002.
200413104024114 is a `hidden beast` number, since 2 + 0 + 0 + 413 + 1 + 0 + 4 + 0 + 241 + 1 + 4 = 666.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 24414322 + ... + 31573490.
It is an arithmetic number, because the mean of its divisors is an integer number (9068663822400).
Almost surely, 2200413104024114 is an apocalyptic number.
200413104024114 is an abundant number, since it is smaller than the sum of its proper divisors (234882759451086).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200413104024114 is a wasteful number, since it uses less digits than its factorization.
200413104024114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7162999 (or 7162996 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 27.
Adding to 200413104024114 its reverse (411420401314002), we get a palindrome (611833505338116).
The spelling of 200413104024114 in words is "two hundred trillion, four hundred thirteen billion, one hundred four million, twenty-four thousand, one hundred fourteen".
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