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2004132401111 = 3461357901147
BaseRepresentation
bin11101001010011111100…
…110011000111111010111
321002121000102200120121002
4131022133212120333113
5230313430343313421
64132404040413515
7264536161222511
oct35123746307727
97077012616532
102004132401111
11702a47546a15
122844b7a7729b
13116cb1732429
146d00162abb1
15371eaba7b0b
hex1d29f998fd7

2004132401111 has 4 divisors (see below), whose sum is σ = 2004190336872. Its totient is φ = 2004074465352.

The previous prime is 2004132401077. The next prime is 2004132401113. The reversal of 2004132401111 is 1111042314002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2004132401111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2004132401113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28915961 + ... + 28985186.

It is an arithmetic number, because the mean of its divisors is an integer number (501047584218).

Almost surely, 22004132401111 is an apocalyptic number.

2004132401111 is a deficient number, since it is larger than the sum of its proper divisors (57935761).

2004132401111 is an equidigital number, since it uses as much as digits as its factorization.

2004132401111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57935760.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 2004132401111 its reverse (1111042314002), we get a palindrome (3115174715113).

The spelling of 2004132401111 in words is "two trillion, four billion, one hundred thirty-two million, four hundred one thousand, one hundred eleven".

Divisors: 1 34613 57901147 2004132401111