Base | Representation |
---|---|
bin | 1001000111010101000011… |
… | …10001100000101111111111 |
3 | 2121222002120022211220201122 |
4 | 10203222201301200233333 |
5 | 10111341112031422421 |
6 | 110343350324501155 |
7 | 4136030001611144 |
oct | 443524161405777 |
9 | 77862508756648 |
10 | 20043031514111 |
11 | 6428224850541 |
12 | 22b858284a7bb |
13 | b25085432a18 |
14 | 4d41332b63cb |
15 | 24b572a892ab |
hex | 123aa1c60bff |
20043031514111 has 16 divisors (see below), whose sum is σ = 20842944807168. Its totient is φ = 19252735334400.
The previous prime is 20043031514053. The next prime is 20043031514171. The reversal of 20043031514111 is 11141513034002.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20043031514111 is a prime.
It is a super-2 number, since 2×200430315141112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20043031514171) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38136131 + ... + 38658123.
It is an arithmetic number, because the mean of its divisors is an integer number (1302684050448).
Almost surely, 220043031514111 is an apocalyptic number.
20043031514111 is a deficient number, since it is larger than the sum of its proper divisors (799913293057).
20043031514111 is a wasteful number, since it uses less digits than its factorization.
20043031514111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 531202.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 20043031514111 its reverse (11141513034002), we get a palindrome (31184544548113).
The spelling of 20043031514111 in words is "twenty trillion, forty-three billion, thirty-one million, five hundred fourteen thousand, one hundred eleven".
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