Base | Representation |
---|---|
bin | 1011101010101100111… |
… | …1000000010110001011 |
3 | 201011101002201201201221 |
4 | 2322223033000112023 |
5 | 11241000440130011 |
6 | 232025333222511 |
7 | 20324060135344 |
oct | 2725317002613 |
9 | 634332651657 |
10 | 200441333131 |
11 | 780089a8326 |
12 | 32a1b491a37 |
13 | 15b948a3040 |
14 | 99b69650cb |
15 | 533209e971 |
hex | 2eab3c058b |
200441333131 has 8 divisors (see below), whose sum is σ = 227220944720. Its totient is φ = 175284728352.
The previous prime is 200441333083. The next prime is 200441333171. The reversal of 200441333131 is 131333144002.
200441333131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 200441333131 - 27 = 200441333003 is a prime.
It is a super-2 number, since 2×2004413331312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 200441333096 and 200441333105.
It is not an unprimeable number, because it can be changed into a prime (200441333171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 405751440 + ... + 405751933.
It is an arithmetic number, because the mean of its divisors is an integer number (28402618090).
Almost surely, 2200441333131 is an apocalyptic number.
200441333131 is a deficient number, since it is larger than the sum of its proper divisors (26779611589).
200441333131 is a wasteful number, since it uses less digits than its factorization.
200441333131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 811503405.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 200441333131 its reverse (131333144002), we get a palindrome (331774477133).
The spelling of 200441333131 in words is "two hundred billion, four hundred forty-one million, three hundred thirty-three thousand, one hundred thirty-one".
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