Base | Representation |
---|---|
bin | 11101001010110000110… |
… | …101010011111010001011 |
3 | 21002121202120201121012010 |
4 | 131022300311103322023 |
5 | 230320023402301011 |
6 | 4132452445351003 |
7 | 264546301563624 |
oct | 35126065237213 |
9 | 7077676647163 |
10 | 2004421525131 |
11 | 703085772093 |
12 | 284578868463 |
13 | 1170295c2a2c |
14 | 6d02bbaca4b |
15 | 372162691a6 |
hex | 1d2b0d53e8b |
2004421525131 has 4 divisors (see below), whose sum is σ = 2672562033512. Its totient is φ = 1336281016752.
The previous prime is 2004421525123. The next prime is 2004421525133. The reversal of 2004421525131 is 1315251244002.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 2004421525131 - 23 = 2004421525123 is a prime.
It is a super-2 number, since 2×20044215251312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2004421525133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 334070254186 + ... + 334070254191.
It is an arithmetic number, because the mean of its divisors is an integer number (668140508378).
Almost surely, 22004421525131 is an apocalyptic number.
2004421525131 is a deficient number, since it is larger than the sum of its proper divisors (668140508381).
2004421525131 is an equidigital number, since it uses as much as digits as its factorization.
2004421525131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 668140508380.
The product of its (nonzero) digits is 9600, while the sum is 30.
Adding to 2004421525131 its reverse (1315251244002), we get a palindrome (3319672769133).
The spelling of 2004421525131 in words is "two trillion, four billion, four hundred twenty-one million, five hundred twenty-five thousand, one hundred thirty-one".
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