Base | Representation |
---|---|
bin | 11101001010110010000… |
… | …001101100110011001111 |
3 | 21002121210222101222012002 |
4 | 131022302001230303033 |
5 | 230320044014100111 |
6 | 4132454442502515 |
7 | 264546634025354 |
oct | 35126201546317 |
9 | 7077728358162 |
10 | 2004441550031 |
11 | 703095aaa098 |
12 | 284583504a3b |
13 | 1170307b459b |
14 | 6d03070262b |
15 | 37217dc263b |
hex | 1d2b206cccf |
2004441550031 has 4 divisors (see below), whose sum is σ = 2073560224200. Its totient is φ = 1935322875864.
The previous prime is 2004441549959. The next prime is 2004441550043. The reversal of 2004441550031 is 1300551444002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2004441550031 - 210 = 2004441549007 is a prime.
It is a super-2 number, since 2×20044415500312 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (29), and also a Moran number because the ratio is a prime number: 69118674139 = 2004441550031 / (2 + 0 + 0 + 4 + 4 + 4 + 1 + 5 + 5 + 0 + 0 + 3 + 1).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2004441549976 and 2004441550003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2004441550081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34559337041 + ... + 34559337098.
It is an arithmetic number, because the mean of its divisors is an integer number (518390056050).
Almost surely, 22004441550031 is an apocalyptic number.
2004441550031 is a deficient number, since it is larger than the sum of its proper divisors (69118674169).
2004441550031 is an equidigital number, since it uses as much as digits as its factorization.
2004441550031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69118674168.
The product of its (nonzero) digits is 9600, while the sum is 29.
Adding to 2004441550031 its reverse (1300551444002), we get a palindrome (3304992994033).
The spelling of 2004441550031 in words is "two trillion, four billion, four hundred forty-one million, five hundred fifty thousand, thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •