200520013 has 4 divisors (see below), whose sum is σ = 201570048. Its totient is φ = 199469980.

The previous prime is 200520011. The next prime is 200520017. The reversal of 200520013 is 310025002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200520013 - 2¹ = 200520011 is a prime.

It is a super-2 number, since 2×200520013² = 80416551227040338, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200519975 and 200520002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200520011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 524731 + ... + 525112.

It is an arithmetic number, because the mean of its divisors is an integer number (50392512).

Almost surely, 2^200520013 is an apocalyptic number.

It is an amenable number.

200520013 is a deficient number, since it is larger than the sum of its proper divisors (1050035).

200520013 is a wasteful number, since it uses less digits than its factorization.

200520013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1050034.

The product of its (nonzero) digits is 60, while the sum is 13.

The square root of 200520013 is about 14160.5089244702. The cubic root of 200520013 is about 585.3099514136.

Adding to 200520013 its reverse (310025002), we get a palindrome (510545015).

The spelling of 200520013 in words is "two hundred million, five hundred twenty thousand, thirteen".