Base | Representation |
---|---|
bin | 11101001011100010011… |
… | …101110111101100001011 |
3 | 21002200220121121221122220 |
4 | 131023202131313230023 |
5 | 230323230041203120 |
6 | 4133111233345123 |
7 | 264606032550033 |
oct | 35134235675413 |
9 | 7080817557586 |
10 | 2005254241035 |
11 | 703472818951 |
12 | 28476b7081a3 |
13 | 11712cc8bb36 |
14 | 6d0aa6128c3 |
15 | 37264404b40 |
hex | 1d2e2777b0b |
2005254241035 has 8 divisors (see below), whose sum is σ = 3208406785680. Its totient is φ = 1069468928544.
The previous prime is 2005254241027. The next prime is 2005254241129. The reversal of 2005254241035 is 5301424525002.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2005254241035 - 23 = 2005254241027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2005254240987 and 2005254241005.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 66841808020 + ... + 66841808049.
It is an arithmetic number, because the mean of its divisors is an integer number (401050848210).
Almost surely, 22005254241035 is an apocalyptic number.
2005254241035 is a deficient number, since it is larger than the sum of its proper divisors (1203152544645).
2005254241035 is a wasteful number, since it uses less digits than its factorization.
2005254241035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 133683616077.
The product of its (nonzero) digits is 48000, while the sum is 33.
Adding to 2005254241035 its reverse (5301424525002), we get a palindrome (7306678766037).
The spelling of 2005254241035 in words is "two trillion, five billion, two hundred fifty-four million, two hundred forty-one thousand, thirty-five".
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