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20053355103053 = 171179609123709
BaseRepresentation
bin1001000111101000010010…
…00110111000001101001101
32122000002012210111120102122
410203310021012320031031
510112023232401244203
6110352214551102325
74136543555640116
oct443641106701515
978002183446378
1020053355103053
116431642190728
1222ba5840719a5
13b2603c189b2c
144d48323cd20d
1524b979065538
hex123d091b834d

20053355103053 has 4 divisors (see below), whose sum is σ = 21232964226780. Its totient is φ = 18873745979328.

The previous prime is 20053355102981. The next prime is 20053355103077. The reversal of 20053355103053 is 35030155335002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12101958991369 + 7951396111684 = 3478787^2 + 2819822^2 .

It is a cyclic number.

It is not a de Polignac number, because 20053355103053 - 220 = 20053354054477 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20053355105053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 589804561838 + ... + 589804561871.

It is an arithmetic number, because the mean of its divisors is an integer number (5308241056695).

Almost surely, 220053355103053 is an apocalyptic number.

It is an amenable number.

20053355103053 is a deficient number, since it is larger than the sum of its proper divisors (1179609123727).

20053355103053 is a wasteful number, since it uses less digits than its factorization.

20053355103053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1179609123726.

The product of its (nonzero) digits is 101250, while the sum is 35.

The spelling of 20053355103053 in words is "twenty trillion, fifty-three billion, three hundred fifty-five million, one hundred three thousand, fifty-three".

Divisors: 1 17 1179609123709 20053355103053