Base | Representation |
---|---|
bin | 101101100110011011110001… |
… | …011001111000011110101001 |
3 | 222022002201000000210010221012 |
4 | 231212123301121320132221 |
5 | 202241331030232412132 |
6 | 1550312520441353305 |
7 | 60146331366325103 |
oct | 5546336131703651 |
9 | 868081000703835 |
10 | 200553253013417 |
11 | 589a217aa05a37 |
12 | 1a5b0692798835 |
13 | 87ba1240ba085 |
14 | 3774b87602573 |
15 | 182bcb4e380b2 |
hex | b666f16787a9 |
200553253013417 has 4 divisors (see below), whose sum is σ = 200553685054800. Its totient is φ = 200552820972036.
The previous prime is 200553253013401. The next prime is 200553253013459. The reversal of 200553253013417 is 714310352355002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 200553253013417 - 24 = 200553253013401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200553253013117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 215323643 + ... + 216253040.
It is an arithmetic number, because the mean of its divisors is an integer number (50138421263700).
Almost surely, 2200553253013417 is an apocalyptic number.
It is an amenable number.
200553253013417 is a deficient number, since it is larger than the sum of its proper divisors (432041383).
200553253013417 is an equidigital number, since it uses as much as digits as its factorization.
200553253013417 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 432041382.
The product of its (nonzero) digits is 378000, while the sum is 41.
The spelling of 200553253013417 in words is "two hundred trillion, five hundred fifty-three billion, two hundred fifty-three million, thirteen thousand, four hundred seventeen".
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