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200553253013117 is a prime number
BaseRepresentation
bin101101100110011011110001…
…011001111000011001111101
3222022002201000000210010112002
4231212123301121320121331
5202241331030232404432
61550312520441352045
760146331366324164
oct5546336131703175
9868081000703462
10200553253013117
11589a217aa05794
121a5b0692798625
1387ba1240b9bb4
143774b876023db
15182bcb4e37e62
hexb666f167867d

200553253013117 has 2 divisors, whose sum is σ = 200553253013118. Its totient is φ = 200553253013116.

The previous prime is 200553253013101. The next prime is 200553253013153. The reversal of 200553253013117 is 711310352355002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 147063425634841 + 53489827378276 = 12126971^2 + 7313674^2 .

It is a cyclic number.

It is not a de Polignac number, because 200553253013117 - 24 = 200553253013101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200553253013317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100276626506558 + 100276626506559.

It is an arithmetic number, because the mean of its divisors is an integer number (100276626506559).

Almost surely, 2200553253013117 is an apocalyptic number.

It is an amenable number.

200553253013117 is a deficient number, since it is larger than the sum of its proper divisors (1).

200553253013117 is an equidigital number, since it uses as much as digits as its factorization.

200553253013117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 94500, while the sum is 38.

The spelling of 200553253013117 in words is "two hundred trillion, five hundred fifty-three billion, two hundred fifty-three million, thirteen thousand, one hundred seventeen".