Base | Representation |
---|---|
bin | 11101001100001001110… |
… | …110001101110111010101 |
3 | 21002202121122211200001011 |
4 | 131030021312031313111 |
5 | 230331103210402431 |
6 | 4133300554332221 |
7 | 264631304422534 |
oct | 35141166156725 |
9 | 7082548750034 |
10 | 2005914934741 |
11 | 703781760903 |
12 | 284914a2a071 |
13 | 117206b18363 |
14 | 6d13027831b |
15 | 372a2410cb1 |
hex | 1d309d8ddd5 |
2005914934741 has 4 divisors (see below), whose sum is σ = 2005964480800. Its totient is φ = 2005865388684.
The previous prime is 2005914934739. The next prime is 2005914934757. The reversal of 2005914934741 is 1474394195002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2005914934741 - 21 = 2005914934739 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2005914934841) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24712251 + ... + 24793288.
It is an arithmetic number, because the mean of its divisors is an integer number (501491120200).
Almost surely, 22005914934741 is an apocalyptic number.
It is an amenable number.
2005914934741 is a deficient number, since it is larger than the sum of its proper divisors (49546059).
2005914934741 is an equidigital number, since it uses as much as digits as its factorization.
2005914934741 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49546058.
The product of its (nonzero) digits is 1088640, while the sum is 49.
The spelling of 2005914934741 in words is "two trillion, five billion, nine hundred fourteen million, nine hundred thirty-four thousand, seven hundred forty-one".
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