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20100311311 = 31364218247
BaseRepresentation
bin10010101110000100…
…100110100100001111
31220212211021121111111
4102232010212210033
5312131134430221
613122311232451
71311050553463
oct225604464417
956784247444
1020100311311
118585113433
123a8b678727
131b843ca042
14d897584a3
157c9982be1
hex4ae12690f

20100311311 has 4 divisors (see below), whose sum is σ = 20164529872. Its totient is φ = 20036092752.

The previous prime is 20100311291. The next prime is 20100311333. The reversal of 20100311311 is 11311300102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20100311311 - 223 = 20091922703 is a prime.

It is a super-2 number, since 2×201003113112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20100311291 and 20100311300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20100311381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32108811 + ... + 32109436.

It is an arithmetic number, because the mean of its divisors is an integer number (5041132468).

Almost surely, 220100311311 is an apocalyptic number.

20100311311 is a deficient number, since it is larger than the sum of its proper divisors (64218561).

20100311311 is an equidigital number, since it uses as much as digits as its factorization.

20100311311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64218560.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 20100311311 its reverse (11311300102), we get a palindrome (31411611413).

The spelling of 20100311311 in words is "twenty billion, one hundred million, three hundred eleven thousand, three hundred eleven".

Divisors: 1 313 64218247 20100311311