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201040343000551 = 1178719170558329
BaseRepresentation
bin101101101101100001011010…
…001110101110010111100111
3222100211021021011112020212001
4231231201122032232113213
5202322321110302004201
61551324354130310131
760226454054030125
oct5555413216562747
9870737234466761
10201040343000551
115906a80457070a
121a66ab70128347
13882403b6b2282
143790594002915
1518397c2492301
hexb6d85a3ae5e7

201040343000551 has 4 divisors (see below), whose sum is σ = 201040514737600. Its totient is φ = 201040171263504.

The previous prime is 201040343000543. The next prime is 201040343000569. The reversal of 201040343000551 is 155000343040102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201040343000551 - 23 = 201040343000543 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201040343000051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84100446 + ... + 86457883.

It is an arithmetic number, because the mean of its divisors is an integer number (50260128684400).

Almost surely, 2201040343000551 is an apocalyptic number.

201040343000551 is a deficient number, since it is larger than the sum of its proper divisors (171737049).

201040343000551 is a wasteful number, since it uses less digits than its factorization.

201040343000551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 171737048.

The product of its (nonzero) digits is 7200, while the sum is 28.

Adding to 201040343000551 its reverse (155000343040102), we get a palindrome (356040686040653).

The spelling of 201040343000551 in words is "two hundred one trillion, forty billion, three hundred forty-three million, five hundred fifty-one", and thus it is an aban number.

Divisors: 1 1178719 170558329 201040343000551