2011011214013 has 4 divisors (see below), whose sum is σ = 2013879989628. Its totient is φ = 2008142438400.

The previous prime is 2011011214007. The next prime is 2011011214073. The reversal of 2011011214013 is 3104121101102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1037193554329 + 973817659684 = 1018427^2 + 986822^2 .

It is a cyclic number.

It is not a de Polignac number, because 2011011214013 - 2⁴ = 2011011213997 is a prime.

It is a super-2 number, since 2×2011011214013² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2011011213982 and 2011011214000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2011011214073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1434386756 + ... + 1434388157.

It is an arithmetic number, because the mean of its divisors is an integer number (503469997407).

Almost surely, 2^{2011011214013} is an apocalyptic number.

It is an amenable number.

2011011214013 is a deficient number, since it is larger than the sum of its proper divisors (2868775615).

2011011214013 is an equidigital number, since it uses as much as digits as its factorization.

2011011214013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2868775614.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 2011011214013 its reverse (3104121101102), we get a palindrome (5115132315115).

The spelling of 2011011214013 in words is "two trillion, eleven billion, eleven million, two hundred fourteen thousand, thirteen".