Base | Representation |
---|---|
bin | 101101101110011010111011… |
… | …110101100011010101111111 |
3 | 222101001011200211020120120020 |
4 | 231232122323311203111333 |
5 | 202324324110142023403 |
6 | 1551413011202023223 |
7 | 60234101521560465 |
oct | 5556327365432577 |
9 | 871034624216506 |
10 | 201102110111103 |
11 | 59093a20489013 |
12 | 1a67ab29947b13 |
13 | 8829b032852b6 |
14 | 379357344a835 |
15 | 183b1d9e03453 |
hex | b6e6bbd6357f |
201102110111103 has 16 divisors (see below), whose sum is σ = 272837762970240. Its totient is φ = 131727553331616.
The previous prime is 201102110111093. The next prime is 201102110111209. The reversal of 201102110111103 is 301111011201102.
It is not a de Polignac number, because 201102110111103 - 24 = 201102110111087 is a prime.
It is a super-2 number, since 2×2011021101111032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201102110111003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1285921825 + ... + 1286078202.
It is an arithmetic number, because the mean of its divisors is an integer number (17052360185640).
Almost surely, 2201102110111103 is an apocalyptic number.
201102110111103 is a deficient number, since it is larger than the sum of its proper divisors (71735652859137).
201102110111103 is a wasteful number, since it uses less digits than its factorization.
201102110111103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2572000486.
The product of its (nonzero) digits is 12, while the sum is 15.
Adding to 201102110111103 its reverse (301111011201102), we get a palindrome (502213121312205).
The spelling of 201102110111103 in words is "two hundred one trillion, one hundred two billion, one hundred ten million, one hundred eleven thousand, one hundred three".
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