Base | Representation |
---|---|
bin | 11101010000111010110… |
… | …010111001010110000111 |
3 | 21010020211012211120011012 |
4 | 131100322302321112013 |
5 | 230422042431141033 |
6 | 4135504400032435 |
7 | 265202140302431 |
oct | 35207262712607 |
9 | 7106735746135 |
10 | 2011031115143 |
11 | 705967700976 |
12 | 28590230271b |
13 | 117840a6443b |
14 | 6d49793d651 |
15 | 374a1666248 |
hex | 1d43acb9587 |
2011031115143 has 4 divisors (see below), whose sum is σ = 2098467250608. Its totient is φ = 1923594979680.
The previous prime is 2011031115077. The next prime is 2011031115187. The reversal of 2011031115143 is 3415111301102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2011031115143 is a prime.
It is a super-2 number, since 2×20110311151432 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (23), and also a Moran number because the ratio is a prime number: 87436135441 = 2011031115143 / (2 + 0 + 1 + 1 + 0 + 3 + 1 + 1 + 1 + 5 + 1 + 4 + 3).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2011031115943) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43718067698 + ... + 43718067743.
It is an arithmetic number, because the mean of its divisors is an integer number (524616812652).
Almost surely, 22011031115143 is an apocalyptic number.
2011031115143 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
2011031115143 is a deficient number, since it is larger than the sum of its proper divisors (87436135465).
2011031115143 is an equidigital number, since it uses as much as digits as its factorization.
2011031115143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87436135464.
The product of its (nonzero) digits is 360, while the sum is 23.
Adding to 2011031115143 its reverse (3415111301102), we get a palindrome (5426142416245).
The spelling of 2011031115143 in words is "two trillion, eleven billion, thirty-one million, one hundred fifteen thousand, one hundred forty-three".
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