Base | Representation |
---|---|
bin | 1001001001010010011000… |
… | …00100011001001101000111 |
3 | 2122012112020022000121121221 |
4 | 10210221030010121031013 |
5 | 10113441410123200403 |
6 | 110434314510421211 |
7 | 4143631206632422 |
oct | 444511404311507 |
9 | 78175208017557 |
10 | 20110313100103 |
11 | 6453810519966 |
12 | 230961b201807 |
13 | b2b518617375 |
14 | 4d74b6c649b9 |
15 | 24d1ae6c8dbd |
hex | 124a4c119347 |
20110313100103 has 4 divisors (see below), whose sum is σ = 20111469746760. Its totient is φ = 20109156453448.
The previous prime is 20110313100079. The next prime is 20110313100107. The reversal of 20110313100103 is 30100131301102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20110313100103 - 217 = 20110312969031 is a prime.
It is a super-2 number, since 2×201103131001032 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20110313100107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 578297248 + ... + 578332021.
It is an arithmetic number, because the mean of its divisors is an integer number (5027867436690).
Almost surely, 220110313100103 is an apocalyptic number.
20110313100103 is a deficient number, since it is larger than the sum of its proper divisors (1156646657).
20110313100103 is a wasteful number, since it uses less digits than its factorization.
20110313100103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1156646656.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 20110313100103 its reverse (30100131301102), we get a palindrome (50210444401205).
The spelling of 20110313100103 in words is "twenty trillion, one hundred ten billion, three hundred thirteen million, one hundred thousand, one hundred three".
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