Base | Representation |
---|---|
bin | 11101010000111110111… |
… | …101111100111000111111 |
3 | 21010021000002120021122212 |
4 | 131100332331330320333 |
5 | 230422213341401421 |
6 | 4135515340331035 |
7 | 265203650325404 |
oct | 35207675747077 |
9 | 7107002507585 |
10 | 2011101122111 |
11 | 7059a3177174 |
12 | 285921843a7b |
13 | 117852406193 |
14 | 6d4a2d642ab |
15 | 374a7893e5b |
hex | 1d43ef7ce3f |
2011101122111 has 4 divisors (see below), whose sum is σ = 2011503106152. Its totient is φ = 2010699138072.
The previous prime is 2011101122099. The next prime is 2011101122117. The reversal of 2011101122111 is 1112211011102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2011101122111 is a prime.
It is a super-2 number, since 2×20111011221112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2011101122117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200984516 + ... + 200994521.
It is an arithmetic number, because the mean of its divisors is an integer number (502875776538).
Almost surely, 22011101122111 is an apocalyptic number.
2011101122111 is a deficient number, since it is larger than the sum of its proper divisors (401984041).
2011101122111 is an equidigital number, since it uses as much as digits as its factorization.
2011101122111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 401984040.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 2011101122111 its reverse (1112211011102), we get a palindrome (3123312133213).
The spelling of 2011101122111 in words is "two trillion, eleven billion, one hundred one million, one hundred twenty-two thousand, one hundred eleven".
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