Base | Representation |
---|---|
bin | 11101010000111111000… |
… | …001010110001011010001 |
3 | 21010021000011020111111220 |
4 | 131100333001112023101 |
5 | 230422214103341423 |
6 | 4135515411355253 |
7 | 265203661023225 |
oct | 35207701261321 |
9 | 7107004214456 |
10 | 2011102012113 |
11 | 7059a3724907 |
12 | 285921bb2b29 |
13 | 1178526582cc |
14 | 6d4a3116785 |
15 | 374a79bc9e3 |
hex | 1d43f0562d1 |
2011102012113 has 8 divisors (see below), whose sum is σ = 2681493310368. Its totient is φ = 1340722694304.
The previous prime is 2011102012093. The next prime is 2011102012123. The reversal of 2011102012113 is 3112102011102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2011102012113 - 25 = 2011102012081 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2011102012092 and 2011102012101.
It is not an unprimeable number, because it can be changed into a prime (2011102012123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2595820 + ... + 3280317.
It is an arithmetic number, because the mean of its divisors is an integer number (335186663796).
Almost surely, 22011102012113 is an apocalyptic number.
It is an amenable number.
2011102012113 is a deficient number, since it is larger than the sum of its proper divisors (670391298255).
2011102012113 is a wasteful number, since it uses less digits than its factorization.
2011102012113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5990223.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 2011102012113 its reverse (3112102011102), we get a palindrome (5123204023215).
The spelling of 2011102012113 in words is "two trillion, eleven billion, one hundred two million, twelve thousand, one hundred thirteen".
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