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201111200203 = 1511331862253
BaseRepresentation
bin1011101101001100101…
…0010110000111001011
3201020002210012111121111
42323103022112013023
511243333431401303
6232220022551151
720346502665514
oct2732312260713
9636083174544
10201111200203
1178322036381
1232b878984b7
1315c705c1aa4
149a3b8d7a0b
155370cbdb6d
hex2ed32961cb

201111200203 has 4 divisors (see below), whose sum is σ = 202443062608. Its totient is φ = 199779337800.

The previous prime is 201111200197. The next prime is 201111200231. The reversal of 201111200203 is 302002111102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201111200203 - 225 = 201077645771 is a prime.

It is a super-2 number, since 2×2011112002032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201111600203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 665930976 + ... + 665931277.

It is an arithmetic number, because the mean of its divisors is an integer number (50610765652).

Almost surely, 2201111200203 is an apocalyptic number.

201111200203 is a deficient number, since it is larger than the sum of its proper divisors (1331862405).

201111200203 is a wasteful number, since it uses less digits than its factorization.

201111200203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1331862404.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 201111200203 its reverse (302002111102), we get a palindrome (503113311305).

The spelling of 201111200203 in words is "two hundred one billion, one hundred eleven million, two hundred thousand, two hundred three".

Divisors: 1 151 1331862253 201111200203