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2011112112131 = 5993637923137
BaseRepresentation
bin11101010000111111100…
…111111000000000000011
321010021000212020122010122
4131100333213320000003
5230422224200042011
64135520412050455
7265204142620313
oct35207747700003
97107025218118
102011112112131
117059a93a3131
12285925463a2b
13117854783555
146d4a45c5443
15374a88153db
hex1d43f9f8003

2011112112131 has 8 divisors (see below), whose sum is σ = 2015025626400. Its totient is φ = 2007200452608.

The previous prime is 2011112112077. The next prime is 2011112112151. The reversal of 2011112112131 is 1312112111102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2011112112131 - 214 = 2011112095747 is a prime.

It is a super-2 number, since 2×20111121121312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2011112112151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1716995 + ... + 2640131.

It is an arithmetic number, because the mean of its divisors is an integer number (251878203300).

Almost surely, 22011112112131 is an apocalyptic number.

2011112112131 is a deficient number, since it is larger than the sum of its proper divisors (3913514269).

2011112112131 is an equidigital number, since it uses as much as digits as its factorization.

2011112112131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 927373.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 2011112112131 its reverse (1312112111102), we get a palindrome (3323224223233).

The spelling of 2011112112131 in words is "two trillion, eleven billion, one hundred twelve million, one hundred twelve thousand, one hundred thirty-one".

Divisors: 1 599 3637 923137 2178563 552959063 3357449269 2011112112131