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2011112143433 = 4342746310179
BaseRepresentation
bin11101010000111111100…
…111111111101001001001
321010021000212022020001222
4131100333213333221021
5230422224202042213
64135520412451425
7265204143110501
oct35207747775111
97107025266058
102011112143433
117059a94146a8
12285925479b75
13117854794883
146d4a45d2a01
15374a881e808
hex1d43f9ffa49

2011112143433 has 4 divisors (see below), whose sum is σ = 2011158497040. Its totient is φ = 2011065789828.

The previous prime is 2011112143373. The next prime is 2011112143489. The reversal of 2011112143433 is 3343412111102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2011112143433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2011112143333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23111663 + ... + 23198516.

It is an arithmetic number, because the mean of its divisors is an integer number (502789624260).

Almost surely, 22011112143433 is an apocalyptic number.

It is an amenable number.

2011112143433 is a deficient number, since it is larger than the sum of its proper divisors (46353607).

2011112143433 is an equidigital number, since it uses as much as digits as its factorization.

2011112143433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46353606.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 2011112143433 its reverse (3343412111102), we get a palindrome (5354524254535).

The spelling of 2011112143433 in words is "two trillion, eleven billion, one hundred twelve million, one hundred forty-three thousand, four hundred thirty-three".

Divisors: 1 43427 46310179 2011112143433