2011112143333 has 2 divisors, whose sum is σ = 2011112143334. Its totient is φ = 2011112143332.

The previous prime is 2011112143211. The next prime is 2011112143343. The reversal of 2011112143333 is 3333412111102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1629957783204 + 381154360129 = 1276698^2 + 617377^2 .

It is a cyclic number.

It is not a de Polignac number, because 2011112143333 - 2⁹ = 2011112142821 is a prime.

It is a super-2 number, since 2×2011112143333² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2011112143298 and 2011112143307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2011112143343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005556071666 + 1005556071667.

It is an arithmetic number, because the mean of its divisors is an integer number (1005556071667).

Almost surely, 2^{2011112143333} is an apocalyptic number.

It is an amenable number.

2011112143333 is a deficient number, since it is larger than the sum of its proper divisors (1).

2011112143333 is an equidigital number, since it uses as much as digits as its factorization.

2011112143333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 2011112143333 its reverse (3333412111102), we get a palindrome (5344524254435).

The spelling of 2011112143333 in words is "two trillion, eleven billion, one hundred twelve million, one hundred forty-three thousand, three hundred thirty-three".