Base | Representation |
---|---|
bin | 1001001001010100000011… |
… | …00010010000011110011001 |
3 | 2122012121112210221000010022 |
4 | 10210222001202100132121 |
5 | 10114000224242333423 |
6 | 110434543513000225 |
7 | 4143662351323136 |
oct | 444520142203631 |
9 | 78177483830108 |
10 | 20111210121113 |
11 | 64541308a7041 |
12 | 230982b6b3075 |
13 | b2b62c409b27 |
14 | 4d756004758d |
15 | 24d213317dc8 |
hex | 124a81890799 |
20111210121113 has 4 divisors (see below), whose sum is σ = 20111219453220. Its totient is φ = 20111200789008.
The previous prime is 20111210121097. The next prime is 20111210121143. The reversal of 20111210121113 is 31112101211102.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It can be written as a sum of positive squares in 2 ways, for example, as 13537667933449 + 6573542187664 = 3679357^2 + 2563892^2 .
It is a cyclic number.
It is not a de Polignac number, because 20111210121113 - 24 = 20111210121097 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20111210121091 and 20111210121100.
It is not an unprimeable number, because it can be changed into a prime (20111210121143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 399923 + ... + 6354711.
It is an arithmetic number, because the mean of its divisors is an integer number (5027804863305).
Almost surely, 220111210121113 is an apocalyptic number.
It is an amenable number.
20111210121113 is a deficient number, since it is larger than the sum of its proper divisors (9332107).
20111210121113 is an equidigital number, since it uses as much as digits as its factorization.
20111210121113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9332106.
The product of its (nonzero) digits is 24, while the sum is 17.
Adding to 20111210121113 its reverse (31112101211102), we get a palindrome (51223311332215).
The spelling of 20111210121113 in words is "twenty trillion, one hundred eleven billion, two hundred ten million, one hundred twenty-one thousand, one hundred thirteen".
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