Base | Representation |
---|---|
bin | 101101101110100100001111… |
… | …011010011011000011100011 |
3 | 222101002010111012011022010122 |
4 | 231232210033122123003203 |
5 | 202330010041132020003 |
6 | 1551421342503350455 |
7 | 60234604242235352 |
oct | 5556441732330343 |
9 | 871063435138118 |
10 | 201112102220003 |
11 | 590981887a3357 |
12 | 1a680a5815242b |
13 | 882aa3643ba80 |
14 | 3793c40517999 |
15 | 183b5c2253238 |
hex | b6e90f69b0e3 |
201112102220003 has 4 divisors (see below), whose sum is σ = 216582263929248. Its totient is φ = 185641940510760.
The previous prime is 201112102219939. The next prime is 201112102220063. The reversal of 201112102220003 is 300022201211102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 201112102220003 - 26 = 201112102219939 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (201112102220063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7735080854603 + ... + 7735080854628.
It is an arithmetic number, because the mean of its divisors is an integer number (54145565982312).
Almost surely, 2201112102220003 is an apocalyptic number.
201112102220003 is a deficient number, since it is larger than the sum of its proper divisors (15470161709245).
201112102220003 is a wasteful number, since it uses less digits than its factorization.
201112102220003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15470161709244.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 201112102220003 its reverse (300022201211102), we get a palindrome (501134303431105).
The spelling of 201112102220003 in words is "two hundred one trillion, one hundred twelve billion, one hundred two million, two hundred twenty thousand, three".
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