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20111533422451 = 139144687290809
BaseRepresentation
bin1001001001010100101001…
…10011100011011101110011
32122012122101100021102011221
410210222110303203131303
510114001410024004301
6110435035542245511
74144003355331502
oct444522463433563
978178340242157
1020111533422451
116454287346129
1223098bba26897
13b2b6813a58b3
144d7590d64839
1524d2318cada1
hex124a94ce3773

20111533422451 has 4 divisors (see below), whose sum is σ = 20256220713400. Its totient is φ = 19966846131504.

The previous prime is 20111533422427. The next prime is 20111533422503. The reversal of 20111533422451 is 15422433511102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20111533422451 - 217 = 20111533291379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20111533426451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72343645266 + ... + 72343645543.

It is an arithmetic number, because the mean of its divisors is an integer number (5064055178350).

Almost surely, 220111533422451 is an apocalyptic number.

20111533422451 is a deficient number, since it is larger than the sum of its proper divisors (144687290949).

20111533422451 is a wasteful number, since it uses less digits than its factorization.

20111533422451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 144687290948.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 20111533422451 its reverse (15422433511102), we get a palindrome (35533966933553).

The spelling of 20111533422451 in words is "twenty trillion, one hundred eleven billion, five hundred thirty-three million, four hundred twenty-two thousand, four hundred fifty-one".

Divisors: 1 139 144687290809 20111533422451