Base | Representation |
---|---|
bin | 1001001001010100101001… |
… | …10011100011011101110011 |
3 | 2122012122101100021102011221 |
4 | 10210222110303203131303 |
5 | 10114001410024004301 |
6 | 110435035542245511 |
7 | 4144003355331502 |
oct | 444522463433563 |
9 | 78178340242157 |
10 | 20111533422451 |
11 | 6454287346129 |
12 | 23098bba26897 |
13 | b2b6813a58b3 |
14 | 4d7590d64839 |
15 | 24d2318cada1 |
hex | 124a94ce3773 |
20111533422451 has 4 divisors (see below), whose sum is σ = 20256220713400. Its totient is φ = 19966846131504.
The previous prime is 20111533422427. The next prime is 20111533422503. The reversal of 20111533422451 is 15422433511102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20111533422451 - 217 = 20111533291379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20111533426451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72343645266 + ... + 72343645543.
It is an arithmetic number, because the mean of its divisors is an integer number (5064055178350).
Almost surely, 220111533422451 is an apocalyptic number.
20111533422451 is a deficient number, since it is larger than the sum of its proper divisors (144687290949).
20111533422451 is a wasteful number, since it uses less digits than its factorization.
20111533422451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 144687290948.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 20111533422451 its reverse (15422433511102), we get a palindrome (35533966933553).
The spelling of 20111533422451 in words is "twenty trillion, one hundred eleven billion, five hundred thirty-three million, four hundred twenty-two thousand, four hundred fifty-one".
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