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20112013311221 = 131547077947017
BaseRepresentation
bin1001001001010101100010…
…11010001011110011110101
32122012200121210021021211002
410210222301122023303311
510114003400401424341
6110435155324053045
74144021303324226
oct444526132136365
978180553237732
1020112013311221
116454503216717
122309a14694185
13b2b729938a50
144d75d89a324d
1524d25dac029b
hex124ab168bcf5

20112013311221 has 4 divisors (see below), whose sum is σ = 21659091258252. Its totient is φ = 18564935364192.

The previous prime is 20112013311217. The next prime is 20112013311259. The reversal of 20112013311221 is 12211331021102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1837884530596 + 18274128780625 = 1355686^2 + 4274825^2 .

It is a cyclic number.

It is not a de Polignac number, because 20112013311221 - 22 = 20112013311217 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20112013311193 and 20112013311202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20112013316221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 773538973496 + ... + 773538973521.

It is an arithmetic number, because the mean of its divisors is an integer number (5414772814563).

Almost surely, 220112013311221 is an apocalyptic number.

It is an amenable number.

20112013311221 is a deficient number, since it is larger than the sum of its proper divisors (1547077947031).

20112013311221 is a wasteful number, since it uses less digits than its factorization.

20112013311221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1547077947030.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 20112013311221 its reverse (12211331021102), we get a palindrome (32323344332323).

The spelling of 20112013311221 in words is "twenty trillion, one hundred twelve billion, thirteen million, three hundred eleven thousand, two hundred twenty-one".

Divisors: 1 13 1547077947017 20112013311221