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20112241432011 = 36704080477337
BaseRepresentation
bin1001001001010101111110…
…00000011001010111001011
32122012201012200112000201020
410210222333000121113023
510114004332301311021
6110435234113323523
74144030043322351
oct444527700312713
978181180460636
1020112241432011
11645460aa661a3
122309a78b665a3
13b2b764c8a871
144d761adc57d1
1524d273b317c6
hex124abf0195cb

20112241432011 has 4 divisors (see below), whose sum is σ = 26816321909352. Its totient is φ = 13408160954672.

The previous prime is 20112241431857. The next prime is 20112241432013. The reversal of 20112241432011 is 11023414221102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20112241432011 - 210 = 20112241430987 is a prime.

It is not an unprimeable number, because it can be changed into a prime (20112241432013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3352040238666 + ... + 3352040238671.

It is an arithmetic number, because the mean of its divisors is an integer number (6704080477338).

Almost surely, 220112241432011 is an apocalyptic number.

20112241432011 is a deficient number, since it is larger than the sum of its proper divisors (6704080477341).

20112241432011 is an equidigital number, since it uses as much as digits as its factorization.

20112241432011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6704080477340.

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 20112241432011 its reverse (11023414221102), we get a palindrome (31135655653113).

The spelling of 20112241432011 in words is "twenty trillion, one hundred twelve billion, two hundred forty-one million, four hundred thirty-two thousand, eleven".

Divisors: 1 3 6704080477337 20112241432011